Do simple checks first .
62 + 2xA = 9 gives a negative A ... .
The first 9 are 0, 1, 1, 2, 3, 5, 8, 13, 21, ... .
The first 9 triangular numbers : 1, 3, 6, 10, 15, 21 , 28, 36, 45.
Subtracting them in order: 1-0 + 3-1 + 6-1 + 10-2 +15-3 +21-5 +28-8 +36-13 +45-21 = ?
The last one can not be true ... .
Minuend is 12 . Please have a look at ry1. And do not forget that mod 9 calculations done as seen in "http://www.shodor.org/succeedhi/succeedhi/
modularmath/negative.html" resurrects the equality.
Let the length of the shortest be accepted as zero. The second will then be 1.5 m. Third will be 3 m. ... .
386 000 000 000 - 127 999 999 999 = ?
Write them under each other, you will soon see that B = 7 .
Evaluate/calculate the paranthesis first.
The first paranthesis is equal to 2800 .
Rounded mean is 55 and the subtrahend should be between 10 and 55 .
II is false ...
A-(A+1)+(A+2)-(A+3)+(A+4)-(A+5)+(A+6)=?
55+60+65+70+75+80+85+90+95- ... = ?
Check if odd number-odd number = even number, the number of places ... etc.
1250-30x30 = ?
This is a pretty generalized form of question 14. We hope you grasp the situation from the images we give.
1 000 000 + 1 000 005 + 1 000 010 + 1 000 015 + 1 000 020 + 1 000 025 + 1 000 030 + 1 000 035
- 1 000 000 - 1 000 004 - 1 000 008 - 1 000 012 - 1 000 016 - 1 000 020 - 1 000 024 = ?
i.e 1+2+3+4+5+6+1 000 035 .
Ax10+180=1880 means 10xA = ?
6xSubtrahend - 23 445 - Subtrahend = 12 795 means 5xSubtrahend = 23 445 + 12 795 = ?
In base 13 coding, the second place from the right has a place value of 13.
The new place values would then be, with unit coefficients (13+1)^{3}, (13+1)^{2}, (13+1) and 1 .
377 - 225 = ? . The real aim of this question is to show how the Fibonacci Numbers get bigger .
The number is 2500-1009= ... But the answer of the question must be 700 less .
This is the feedback!