G+B=N where G is the number of girl visitors, B is of boy visitors and N is of G total visitors. 4xG=N . G+54=B .
This all say : G+54+G = 4xG i.e. G = 54/2
Let the dividend be AB (A&B are digits) and the quotient CA. AB=5xCA + 3 should be valid .
10xA + B = 50xC + 5xA + 3 and 5xA + B = 50xC + 3 . C must then be 1 otherwise A and B can not cope with. This means 5xA + B = 53 . Not many
choices !
840/35 = 24. If 25 bricks high, then 25x34 = 850 for which not enough bricks.
7750/62 = ? but we know 60x125=6x1250=3x2500=7500 .
Have please a look at ry1 .
63 000 000 000 000 / 7 000 000 000 = 63 000 / 7 = ?
The denominator should always be, also working with complex numbers, as simple as possible. Evaluate 320+280 first. It is 600 and all numbers in
the numerator are divisible by 600 .
The pattern at the denominator should be ...2xn ... Its sum will be 30.
385/30 = 77/6 = 72/6 + 5/6 = 12+ ...
The first 8 primes are 2,3,5,7,11,13,17 and 19. First divide the number by 2x3x5=30 to get 9 376 367. If you can not this way, then divide first
by 2, then by 3, by 5 etc.
The area is 1 412 000 000 m2 and this should be divided by 300
In general 2x3x4x5x6x7 + 1 satisfies the conditions with the exception of being the least .
Check given in III applied to 169 367 : -7+6-3+9-6+1 = 0 .
The result should be zero !
Some may live 130 years, though rare.
IV is obviously not wrong .
mod 9 count is blind to errors of multiples of 9.
Please have a look at ry1.
We have $1459 for 30 days for the other expenses .
305407 > 7 x 42000 .
3009/5 is approximately 602 whereas 5050/11 is nearly 459 .
The quotient does not have 1 at ones, many facts indicate this .
220 < 1570 .
100/99 is approximately 1.01 .
282/6 = ?
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