First make the additions, adding terms with positive and negative signs separately (and without mixing). Then subtract the second sum from the
If there are some cancelling, let them cancel; be carefull by the way !
5/98 - 5/100 is being asked .
Apply the method given in question 2..
a and b are not likely .
the common denominator is 144 .
The first sale will be 2 1/2 kg .
Only he choices a and c are plausible. Use trial and error method.
Before tailor pants should be 130 cm. (1/25 ths of it makes 5.2 cm but rounding makes 5 cm. )
If hte original length is 144 cm. it will shrink 14.4 cm but rounding will give 14 cm.
The second day he drives 960 km. 960/25 = 192/5 = 384/10 .
The first day he took 1000 km, the second day 960 km. , the third day 921.6 , the fourth day 884.736 and the fifth day 849.346 km.
Rounding we get respectively : 1000 , 960 , 923, 886 and 851 (or 1000 , 860 , 922 , 885 and 849) depending on the way we round) with a total of ... .
If you solved the previous question explicitly, rounding or not rounding ... .
This is just like the previous question, to have fresh breathe .
By subtraction signs are an integral part of the operands.
I have $ 100 and spend 1/10 ths. There stays $ 90. I gain 1/10 ths and I have $ 99 .
First decreasing for ten hours and then increasing and staying a little bit below ... .
In which case are the operands nearest to each other ?
After the first ms. the speed is 90 km./hours which is reduced by 91/10 km./hours in the second ms.
The normal way of solving is prone to errors if not done with care.
60 is really a good number which is evenly divisible by many of its preliminaries, try using it as the denominator.
If tere originally were 60 passengers 24 got a cab, there remained 36.
12 got metro and there remained 24.
8 of them made a call and ... and the fraction of remainings is 16/60
Reduce 16/60 to simplest form and ... .
First reduce the subtrahend, only the subtrahend .
It is equal to 1+27/18-17/9 = 1+(27-34)/18 .
10/150 is equivalent to 1/15 .
Time does not stop as we are in infinite loops.
Choice d must be around 0.25 .
Naturally the other half .
(1000 - 999)/... .
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