FOURTH GRADE / MATHEMATICS / DIVISION of NATURAL NUMBERS 1.1
MATHEMATICS IS EASY. PROVIDED THAT ONE WORKS ENOUGH .
ENOUGH IS SKILL DEPENDENT, HAVE TO FIND "ENOUGH" RIGHT FOR YOU.
The elements of division are nemed as dividend, divisor and quotient ... .
how is the "number" to be determined ...
Max poss. remainder will be 1 less than divisor (for natural numbers) .
It should be divisible by 5 .
24x358 = 35800/4 - 358 = 17900/2 - 358 = 8950 - 358 = 8600 - 8 = 8592 .
6 may be subtracted 100 times and there remains 798.
Repeating the same there remains 198.
Subtracting 6 an additional 10 times leaves 138 behind ...
Remember always that somthing called place value exits .
The sum of natural numbers from 1 to 10 is ... .
February must have 29 days .
Division is the inverse operation of multiplication .
The question is directed to understanding one of the existing "so called" rules .
Find first the price of a gum in cents .
If both sides of an equation is divided by the same number nothing changes .
So is it with the numeator and the denominator. Division of both dividend and divisor by the same number, e.g. 10, 100 or 1000, etc. does not affect the result
In case of equal shares the length is 6/2 m.
Multiplications are first .
10010000/1001 + 1001/1001 .
The quotient should be 11 and 88880+8888 = ... ?
the remainder of 11110/3702 is ?
check if a division is the basic operation, e.g. 3807/1269 = ? .
Subtract 100 from both sides of the equation and find the numerical value of 5xA .
change first all units to cm. and g. .
Since the divisor is a 2-digit number, write the dividend as 1100 + 11 .
First are divisions due .
Trial and error is rational . Multiply the numbers given in the choices by 13 and check which one gives a 7 at ones ...
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